Sunday, November 24, 2013

Swot Analysis Of Mercedes

[pic] Wiam Hebbesni (Collabo rolld with Manal Douirmi) GBU 3301-01 Professor: Ahlam Fakhar 08/10/2009 Homework 2 3.5) The nonrepresentational cockeyed set out of return = [(1+0.1) (1+0.3)] ^1/2 - 1 = 19.58% 3.9) a. regard as= 25 average= 24 Mode= 23 b. S²= 35.46 S= 5.95 range= 26 Coefficient of stochastic variable= 23.8 % Z scads: -0.16; 0; 1.51; -0.16; -0.33; -0.16; -0.17; -0.33; -0.33; -0.33; -0.33; 3.19; -0.16; -0.33; -0.50; -0.33 c. Yes, the data is skewed to the right because the mean is high than the medial. d. xxxxxxxxxxxxxxxxxxxxxxxxxxx 3.15) a. Mean= 4.28 Median= 4.5 b. S²= 2.68 S= 1.63 Range= 6.08 Coefficient of Variation= 29.27% Z scores: âˆ0.05; 0.77; âˆ0.77; 0.51; 0.30; âˆ1.19; âˆ0.46; âˆ0.66; 0.1;3 1.11; âˆ2.39; 0.51; 1.33; 1.16; âˆ0.30 There be no outliers c. The diffusion is left-skewed because the mean is lower than th e median. d. Since the mean and the median are both under 5 legal proceeding and the dispersion is left-skewed, this means that the majority of the observations are less(prenominal) than 5 minutes. However, 6 of the observations have waited to a greater extent than 5 minutes.
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Therefore, regular if the customer is more than likely to be served in less than 5 minutes but non at cytosine%, the manager was indisputable that the customer would almost certainly not wait more than 5 minutes. 3.17) a. The geometric mean rate of increase = [(1+0.208) (1- 0.016)] ^1/2 -1 = 9.02% b. The value of ¥ potassium at the end of 2005= 1000(1+9.02%) = ¥1090.2 ! c. At the end of 2005, the value of ¥1000 in Problem 3.18 allow for be ¥1062 which is less than the value of ¥1000 in this problem. d. The geometric mean rate of increase = [(1+0.208) (1- 0.016) (1+0.068)] ^1/3 -1 = 8.27% 3.43) a. cov(X,Y) = 29.61 b. Sx²= 21.76 Sy²= 195.87 Coefficient of correlativity r= 0.45 c. The linear relationship amid X and Y is positive and moderate because r=0.45 3.80) a. b. c. d.If you fate to get a full essay, order it on our website: BestEssayCheap.com

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